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Please help with physics problem?!?
This is the first part of the question I found the answer and I am entitled: Drilling used by most dentists today is powered by a small wind turbine which can operate at speeds of angular 307,000 rpm. These exercises, as well as ultrasound turbine dental drills are the fastest in the world - though more than the angular velocity of the jet engine. Suppose that starts at rest and exercise at the operating speed of 2.17 sec Calculate acceleration angle produced by the drilling, assuming it is constant. To answer in rev / s Do not enter the unit. 2.36 × 10 ^ 3, I can not get the second part to the work. Please help! How we do a lot of turns of the strand as it approaches the speed?
Because the acceleration of the drill is supposed to be constant in question, and you know the drill begins to relax and ends at 307,000 rpm min 2.17 s, you know the average number of rounds of 2.17 s is half the final speed (153,500 rpm). This is true only because the acceleration is constant. 2.17 s is 0.03617 minutes, so the number of speed is 153 500 x 0.03617 = 5.552. The way we work and what (which also works when the acceleration is not constant) is to draw a graph of the angular velocity (rpm) versus time (in minutes). The area under the curve then gives the number of turns.